In this paper, we established some new Hermite-Hadamard-type inequalities for differentiable convex functions via Reimann-Liouville fractional integrals. Moreover, our results improve and extend the corresponding ones in the literature.
Keywords: integral inequalities, Riemann-Liouville fractional integral, Hermite-Hadamard inequality, convex function, Hölder inequality
Received August 06, 2016; Revised September 12, 2016; Accepted September 24, 2016
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The following definition is well known in the literature.
Definition 1.1. [7, 8] A function: is said to beconvex on the interval
if for all
and
satisfies the following inequality:
![]() |
Many significant inequalities have been studied for the class of convex functions, but the most important is the following inequality
![]() | (1) |
that is known as Hermite-Hadamard inequality [1]. For more systematic information, please refer to the monographs [3-8][3] and closely related references therein.
In what follows we recall the following definition [9].
Definition 1.2. Let The left Riemann-Liouville fractional integrals
and
of order
are defined by
![]() |
and
![]() |
respectively. Here, is the gamma function
and
Tomar et. al. [2] established the following Hermite-Hadamard type inequalities via Riemann-Liouville fractional integrals:
Lemma 1.1. Let be twice differentiable mapping on the interior
of an interval
such that
where
with a < b. Then for each
and
the following equality holds:
![]() | (2) |
where
![]() |
Theorem 1.1. The assupmtions of Lemma 1.1 are satisfied. If is convex on
, then for each
the following inequality holds:
![]() | (3) |
Theorem 1.2. The assupmtions of Lemma 1.1 are satisfied. If is convex on
for
then the following inequality holds:
![]() | (4) |
where
Theorem 1.3. Let the assupmtions of Lemma 1.1 be satisfied. If is convex on
for
then the following inequality holds:
![]() | (5) |
The main objective of this article is to establish some Hermite-Hadamard type inequalities for convex functions via Riemann-Liouville fractional integrals. Our results improve and generalize some types of Hermite-Hadamard inequalities in [2].
We start with the following lemma:
Lemma 2.1. Let be twice differentiable mapping on the interior
of an interval
such that
where
with
Then for each
and
the following equality holds:
![]() | (6) |
where
![]() |
and
Proof. Denoting
![]() | (7) |
Integrating by parts twice and changing variable of definite integral, we have
![]() | (8) |
and similarly
![]() | (9) |
Using equations (8)-(9) in (7) and by the simple calculations, we obtain the desired result.
Remark 2.1. If we take in Lemma 2.1, then the identity (6) reduces to the identity (2) which was proved by Tomar et. al. [2].
Theorem 2.1. The assupmtions of Lemma 1.1 are satisfied. If is convex on
then for each
the following inequality holds:
![]() | (10) |
Proof. From Lemma 2.1, we have
![]() |
Now, since is convex, we have
![]() |
and this ends the proof.
Remark 2.2. If we take in Theorem 2.1, then inequality (10) reduces to (3).
Theorem 2.2. The assupmtions of Lemma 1.1 are satisfied. If is convex on
for
then the following inequality holds:
![]() | (11) |
where
Proof. From Lemma 2.1 and using the well known Hölder integral inequality, we have
![]() | (12) |
Since is convex, then we have
![]() | (13) |
and
![]() | (14) |
Thus, if we use (13) and (14) in (12), we obtain
![]() |
this completes the proof of first part of the Theorem.
Let
and
for
Using the fact that
for
and
we find
![]() |
which completes the proof of last part of the Theorem. This completes the proof.
Remark 2.3. If we choose in Theorem 2.2, then inequality (11) reduces to (4).
Theorem 2.3. Let the assumptions of Lemma 1.1 be satisfied. If is convex on
for
then the following inequality holds:
![]() | (15) |
Proof. From Lemma 2.1 and using the well known power mean inequality, we have
![]() | (16) |
Since is convex, then we have
![]() | (17) |
and
![]() | (18) |
Combining equations (16), (17) and (18), we obtain inequality (15) as required.
Remark 2.4. If we choose in Theorem 2.3, then inequality (15) reduces to (5).
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