Keywords: Coupled fixed point, partial ordered, complete metric space
American Journal of Mathematical Analysis, 2014 2 (2),
pp 19-22.
DOI: 10.12691/ajma-2-2-1
Received March 23, 2014; Revised April 12, 2014; Accepted April 13, 2014
Copyright © 2013 Science and Education Publishing. All Rights Reserved.
1. Introduction
The famous and probably the well known fixed point theorem is the Banach Contraction Principle. It has been extended and improved by many athematicians. Its significance lies in its vast applicability in a number of branches of mathematics. Recently, W. Zhong et al [11] give the existence and uniqueness of solutions to the Cauchy problem for the local fractional differential equation with fractal conditions in a generalized Banach space.
In 2006, Bhaskar and Lakshmikantham [3] established some coupled fixed point theorem on ordered metric spaces and give some application in the existence and uniqueness of a solution for periodic boundary value problem. Ciric and Lakshmikantham [5] later on investigated some more coupled _xed point theorems in partially ordered sets. Also, many researchers have obtained coupled fixed point results for mappings under various contractive conditions in the framework of partial metric spaces [1, 2, 4, 6].
In this paper, we prove some unique coupled fixed point theorems in a complete metric space endowed with a partial order. At the end of this paper we give an example to support our main theorem.
The organization of this paper is as follows. In section 2, the preliminary result on partial metric space is discussed. In section 3, we investigated the necessary condition for the uniqueness of coupled fixed point of the given mapping in partially ordered metric space and give an example to illustrate our main theorem.
2. Preliminaries
In this section, we give some definitions, lemma which are useful for main result in this paper.
Definition 2.1. [3, 5] An element
is said to be coupled fixed point of the mapping
if 
Definition 2.2. [3] Let
be a partially ordered set and
We say that
has the mixed monotone property if
is monotone non-decreasing in x and is monotone non-increasing in
that is, for any 
and
Definition 2.3. [7, 8, 9] Let
be a non empty set. A partial metric on
is a function
such that for all 
(P1) 
(P2) 
(P3) 
(P4) 
A partial metric space is a pair
such that
is a non empty set and
is a partial metric on
.
If
is a partial metric on
, then the function
given by
is a metric on
.
Definition 2.4. [7, 8, 9] Let
be a partial metric space. Then:
(a) a sequence
in partial metric space
converges to a point
if and only if 
(b) a sequence
in partial metric space
converges to a point
if and only if
if and only if 
(c) a sequence
in partial metric space
is called a cauchy sequence if there exists (and is finite) 
(d) a partial metric space
is said to be complete if every cauchy sequence
in
converges to a point
, that is 
Lemma 2.5. [7, 8] Let
be partial metric space;
a.
is cauchy sequence in
if and only if it is Cauchy sequence in the metric space 
(b) a partial metric space
is complete if and only if the metric space
is complete; furthermore,
iff

3. Main Theorem
Theorem 3.1. Let
be a partially ordered set and let p be a partial metric on
such that
is complete. Suppose the mapping
satisfies the following condition for all
we have
1)
is continuous or
2)
has the following properties,
(a) if a non-decreasing sequence
in
converges to some point
then
(b) if a non-increasing sequence
in
converges to some point
then 
3)
such that
and 
4)
is a continuous and non decreasing function such that it is positive in
and 
 | (3.1) |
Then
has a coupled fixed point 
Proof: Choose
and set
and
Repeating this process, set
and
Then by (3.1), we have
 | (3.2) |
and similarly,
 | (3.3) |
By adding, we have
 | (3.4) |
Let
If
such that
then
and
is fixed point of
and the proof is finished. In other case
for all
Then by using assumption on
, we have,
 | (3.5) |
is a non - negative sequence and hence posses a limit
Taking limit when
, we get,
and consequently
By our assumption on
, we conclude
ie. 
 | (3.6) |
Next, we prove that
,
are cauchy sequences. Suppose that at least one
or
be not a cauchy sequence. Then
and two subsequence of integers
with
such that
 | (3.7) |
Further, corresponding to
we can choose
in such a way that it is smallest integer with
satisfying equation (3.7), we have
 | (3.8) |
Using (3.7) and (3.8) and triangle inequality, we get
 | (3.9) |
Letting
and using (3.6), we have
Now, we get
 | (3.10) |
similarly,
 | (3.11) |
Using(3.10) and (3.11), we get
 | (3.12) |
taking
of both sides of equation (3.12) from
it follows that
which is a contraction. Therefore
and
are cauchy sequences. By lemma (2.5),
and
are cauchy sequence in
. Since
is complete, hence
is also complete, so
such that
By lemma, we have
By condition and equation, we get
It follows that
Similarly,
We now prove that
. We shall distinguish the cases (1), 2(a) and 2(b) of the Theorem 3.1.
Since
is a complete metric space,
such that
We now show that if the assumption (1) holds, then
is coupled fixed point of 
As, we have
and
Suppose now that the condition 2(a) and 2(b) of the theorem holds.
The sequence
, 
Letting
, we have
This implies that
similarly, we can show that
This completes the theorem.
Theorem 3.2. Let the hypotheses of Theorem 3.1 hold. In addition, suppose that there exists
which is comparable to
and
for all
. Then
has a unique coupled fixed point.
Proof: Suppose that there exists
are coupled fixed points of
Consider the following two cases:
Case1:
and
are compareable. We have
similarly,
It follows that
So,
The proof is complete.
Case 2: Suppose now that
and
are not compareable. Choose an element
compareable with both of them.

So,
The proof is complete.
Example 3.3. Let
endowed with the usual partial metric p defined by
with
The partial metric space
is complete because
is complete for any 
Thus
is Euclidean metric space which is complete.
Consider the mapping
defined by 
Let us take
such that 
Clearly
is continous and has the mixed monotone property. Also there are
in
such that
Then it is obvious that
is the coupled fixed point of 
Now, we have following possibilities for values of
and
such that 
Thus all the conditions of theorem 3.1 are satisfied.
Therefore
has a coupled fixed point in 
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