Article Versions
Export Article
Cite this article
  • Normal Style
  • MLA Style
  • APA Style
  • Chicago Style
Research Article
Open Access Peer-reviewed

A Short Proof of Von Neumann’s Conjecture

Bahman Mashood
American Journal of Mathematical Analysis. 2022, 10(1), 1-2. DOI: 10.12691/ajma-10-1-1
Received September 22, 2022; Revised October 27, 2022; Accepted November 08, 2022

Abstract

Let H be a separable Hilbert space and let B(H) be the set of all bounded operators acting on H. Given TB(H), we show that T has a proper invariant subspace, i.e., there exists a proper Hilbert subspace LH such that T(L)⊆L. This problem has only been solved for special cases so far and in this article we try to offer a solution that can take care of the most general cases.

1. Main Arguments

The preliminary definitions and notations can be found in the thesis of Jonathan Noel “The invariant subspace problem”, Department of Mathematics and Statistic, Thompson River University, 2011.

Given T as in the above, without loss generality, we can assume that is one to one and onto, otherwise T will have an proper invariant subspace. So if is any vector in then the subspace which is spanned by the elements of the form will be equal to , because is invariant under the action of . Thus any element can be written as a norm convergent sum, , where is a complex number. Before we propose the general solution, we consider the following special case. Suppose we have , defined by with

Lemma 1.1. If for some vector , then has a proper invariant subspace.

Proof. Let be the roots of the polynomial Hence we have Then at least one of the factors, say , is not invertible. This implies that either has a proper invariant subspace, or there exits an integer with which implies the existence of a one dimensional invariant subspace for

The case of , with , is much more complex and Lemma 1 is not working for this case. At this point we assume that , and . Next, let us pick an element , with . Now it is well known that a subset of is compact if every sequence in has a bounded subsequence with its limits included in . Next, consider the following set, Subsequently, define the following set to be the subset of the closure of convex hall of consisting of all elements of the form , with .

It is easy using the above comment to check that is a convex and compact subset of Hence by the Brower fixed point theorem there exists an element in for which If is different from zero then we have a non trivial invariant subspace and we are done. Otherwise, we have to consider the case where This means we have But assuming that does not have a non trivial invariant subspace implies that for every where, by the above, each and .

Next, let us denote . Then continue the above argument for each If for any integer the subspace generated by the set , will not span , then this implies that has a non trivial invariant subspace, otherwise the Brower fixed point acting over the compact convex hall of the above set implies the existence of a fixed point under the action of , in which case we have the following infinite dimensional polynomial with .

On the other hand, if we have a nontrivial fixed point then the proof is complete. As we mentioned in the above if does not have nontrivial invariant subspace we get that the polynomial converges in norm topology to zero. But considering the fact that and therefore the sets have a following limit point with and this will implies contradiction since as tends to infinity this will force to be equal to zero. This proves the final theorem which is the main focus of this article.

Theorem 1.2. Every Bounded Operator acting on a separable Hilbert space has a proper invariant subspace.

References

[1]  R. Abraham, J.E. Mardsen, T.Ratiu. “Manifolds, Tensor Analysis and applications”.
In article      
 
[2]  Jonathan Noel, “The invariant subspace problem”, Thesis, Department of Mathematics and Statistic, Thompson River University, 2011.
In article      
 

Published with license by Science and Education Publishing, Copyright © 2022 Bahman Mashood

Creative CommonsThis work is licensed under a Creative Commons Attribution 4.0 International License. To view a copy of this license, visit https://creativecommons.org/licenses/by/4.0/

Cite this article:

Normal Style
Bahman Mashood. A Short Proof of Von Neumann’s Conjecture. American Journal of Mathematical Analysis. Vol. 10, No. 1, 2022, pp 1-2. https://pubs.sciepub.com/ajma/10/1/1
MLA Style
Mashood, Bahman. "A Short Proof of Von Neumann’s Conjecture." American Journal of Mathematical Analysis 10.1 (2022): 1-2.
APA Style
Mashood, B. (2022). A Short Proof of Von Neumann’s Conjecture. American Journal of Mathematical Analysis, 10(1), 1-2.
Chicago Style
Mashood, Bahman. "A Short Proof of Von Neumann’s Conjecture." American Journal of Mathematical Analysis 10, no. 1 (2022): 1-2.
Share
[1]  R. Abraham, J.E. Mardsen, T.Ratiu. “Manifolds, Tensor Analysis and applications”.
In article      
 
[2]  Jonathan Noel, “The invariant subspace problem”, Thesis, Department of Mathematics and Statistic, Thompson River University, 2011.
In article